ISBN Number in Java – ISC 2013 Practical Question

Question:

An ISBN (International Standard Book Number) is a ten digit code which uniquely identifies a book.

The first nine digits represent the Group, Publisher and Title of the book and the last digit is used to check whether ISBN is correct or not.

Each of the first nine digits of the code can take a value between 0 and 9. Sometimes it is necessary to make the last digit equal to ten; this is done by writing the last digit of the code as X.

To verify an ISBN, calculate 10 times the first digit, plus 9 times the second digit, plus 8 times the third and so on until we add 1 time the last digit. If the final number leaves no remainder when divided by 11, the code is a valid ISBN.

For Example:

1. 0201103311 = 10*0 + 9*2 + 8*0 + 7*1 + 6*1 + 5*0 + 4*3 + 3*3 + 2*1 + 1*1 = 55

Since 55 leaves no remainder when divided by 11, hence it is a valid ISBN.

2. 007462542X = 10*0 + 9*0 + 8*7 + 7*4 + 6*6 + 5*2 + 4*5 + 3*4 + 2*2 + 1*10 = 176

Since 176 leaves no remainder when divided by 11, hence it is a valid ISBN.

3. 0112112425 = 10*0 + 9*1 + 8*1 + 7*2 + 6*1 + 5*1 + 4*1 + 3*4 + 2*2 + 1*5 = 71

Since 71 leaves no remainder when divided by 11, hence it is not a valid ISBN.

Design a program to accept a ten digit code from the user. For an invalid input, display an appropriate message. Verify the code for its validity in the format specified below:

Test your program with the sample data and some random data:

Example 1

INPUT CODE: 0201530821

OUTPUT : SUM = 99
LEAVES NO REMAINDER – VALID ISBN CODE

Example 2

INPUT CODE: 035680324

OUTPUT : INVALID INPUT

Example 3

INPUT CODE: 0231428031

OUTPUT : SUM = 122
LEAVES REMAINDER – INVALID ISBN CODE

```import java.io.*;
class ISBNumber
{
public static void main(String[] args) throws IOException
{
long isbnNumber;
int s = 0, i, t, d, dNumber;
String st;

System.out.print("Input a 10-digit ISBN number: ");

// check the length is 10
st = "" + isbnNumber;
if (st.length() != 10)
{
System.out.println("Illegal ISBN");
return;
}

s = 0;
for (i = 0; i < st.length(); i++)
{
d = Integer.parseInt(st.substring(i, i + 1));
dNumber = i + 1;
t = dNumber * d;
s += t;
}

// check the number s is divisible by 11 or not
if ((s % 11) != 0)
System.out.println("Illegal ISBN");
else
System.out.println("Legal ISBN");
}
}```